The results above are not independent. Each interlock is a single structural input that fixes two results simultaneously — in different domains, with no additional freedom.
Projector universality SC
$P[Q] = \dfrac{4\pi}{3}\,\mathrm{tr}\,Q$
Same projector in muon and proton. Only the trace changes — the projector carries no freedom between sectors.
Muon: $\mathrm{tr} = 5\pi^2/d$ · Proton: $\mathrm{tr} = N_p^2\pi^2/d^2$
Per-route normalisation SC
$|a_0|^2 = \dfrac{\pi^2}{d}$
Locked by the same three [SC] inputs in both lepton and dualcore sectors: curvature quantum $\pi$, quadratic functional, isotropic share $1/d$.
Locks muon node cost, proton baseline, and $m_p/m_\mu = 80/9$ simultaneously
Casimir function — two levels SC
$\dfrac{1}{2\,C_F(SU(d))}\bigg|_{d=2} = \dfrac{2}{3} \qquad \bigg|_{d=3} = \dfrac{3}{8}$
Same formula at two levels: $d=2$ gives Koide $Q=2/3$; $d=3$ gives electron baseline exponent $3/8$. Any $\kappa\neq 1$ breaks the $d=2$ check.
$1/d$ ratio — three appearances SC
$\text{projector}\;\tfrac{4\pi}{3},\quad f'(0) = -\tfrac{1}{3},\quad \text{impedance share}\;\tfrac{1}{d}$
Three structurally independent appearances of the same architectural ratio, all forced by $(d_T,d_V)=(2,1)$. Not reparameterisations of each other.
Gauge-completion interlock SC PL
$U(1)_{\mathrm{wind}} \times SU(2)_{T\text{-routing}} \times SU(3)_{\mathrm{seam}} \Rightarrow SU(3)\times SU(2)\times U(1)$
The gauge product is not inserted as a separate symmetry assumption. $U(1)$ comes from integer tangential winding, $SU(2)$ from the two-channel complex tangential routing doublet, and $SU(3)$ from the three-packet dualcore seam. The same $N_c=3$ seam count also supports confinement and the anomaly-balance colour factor, so the sectors cross-lock rather than float independently.
Origins: winding phase · tangential doublet · seam triplet · Casimir reciprocity $C_F(SU(2))C_F(SU(3)) = 1$
Firewall: gauge-group language is projection bookkeeping; the underlying structural claim is routing geometry, not gauge-field ontology.
Proton/muon ratio — derived cross-check SC
$\dfrac{m_p}{m_\mu} = \dfrac{N_p^2}{5d^2} = \dfrac{400}{45} = \dfrac{80}{9} \approx 8.889$
Not an independent prediction — the ratio of two projector outputs, each already locked. Agreement with experiment (+0.10%) confirms mutual consistency of the projector normalisation and route count across sectors.
$80/9 = 8.889$ (BCT) vs $8.880$ (exp) · +0.10%